The top length of the container is 145", the bottom length is 38", the width of the container is 31", and the height is 39".
2007-08-06 09:07:59 · 6 answers · asked by Steven B 1 in Science & Mathematics ➔ Mathematics
the cross-sectional area is
A = (top + bottom) x height / 2 = (145 + 38 ) x 39 /2
= 183 x 39 /2 = 3568.5 sq.in.
the volume V = Area x width = 3568.5 x 31
= 110623.5 cu. in
1 cu ft = 1728 cu. in
so volume = 110623.5 / 1728
= 64.02 cu. ft
2007-08-06 09:40:37 · answer #1 · answered by vlee1225 6 · 0⤊ 0⤋
sounds like you have a trapezoidal based container...if so try:
.5(145+38) X 39 X 31
THE ANSWER YOU GET WILL BE IN CUBIC INCHES...CONVERT TO CUBIC FEET BY DIVIDING BY 12^3
2007-08-06 16:14:20 · answer #2 · answered by plb5000 3 · 0⤊ 0⤋
I have trouble picturing this container from your description.
Basically you need to break it down into standard shapes.
It sounds like you have a cubic core: 38" x 31" x 39".
That translates into 45,942 cu. in.
Then you have 2 triangular prisms: 53.5" x 31" x 39".
Together they would make a cube of 64,681.5 cu.in.
The total volume would be 110,623.5 cu.in.
To convert to cubic feet, divide by 1728.
So 64.02 cu.ft.
2007-08-06 16:24:12 · answer #3 · answered by Robert S 7 · 0⤊ 0⤋
31*38*39
2007-08-06 16:17:35 · answer #4 · answered by Anonymous · 0⤊ 1⤋
"Quadrilateral" is really only used for 2-D objects. Is this a frustum (pyramid with the chop topped off, giving trapezoidal sides)? With the sides and faces being symmetrical?
2007-08-06 16:15:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Is it essentially a section of a pyramid, or are two sides parallel?
2007-08-06 16:13:37 · answer #6 · answered by supastremph 6 · 0⤊ 0⤋