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f(x) = log(sub 1/3) (9x)

2007-08-06 06:05:31 · 2 answers · asked by Jenny V. 2 in Science & Mathematics Mathematics

2 answers

1) x can not be 0 so domain is x>0 strictly. 0 has NO logarit.
2 Range - infinity to+ infinity not (1,+infinity)Observation,There are a lot of wrong things in the preceding answer.Be very careful

2007-08-06 07:07:57 · answer #1 · answered by santmann2002 7 · 0 0

Hi,

Well the domain is the set of values that can be inputted in and will yield a valid answer. For logarithmic functions (regardless of base as long as it is a real number) the domain is (0,inf) or if you prefer x>= 0. That means that all real numbers greater than x are in the domain.

As for the range, you need to look at the function values based on its domain. Since all logarithms equal 1 at x=0 regardless of base,

f(0) = 1
as for the upper range the logarithm function is unbounded as x----> inf.

so the range would be (1, inf)

Hope that helps,
Matt

2007-08-06 13:37:38 · answer #2 · answered by Matt 3 · 0 0

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