A rectangle had a length of 12 feet and a diagonal of 13 feet. What was its width?

Answer 1

In a rectangle, the length and width are legs of a right triangle whose hypotenuse is the diagonal. By the Pythagorean theorem:

L^2 + W^2 = D^2
12^2 + W^2 = 13^2
144 + W^2 = 169
W^2 = 25
W = 5

Also, 5:12:13 is one of those right triangles that (like 3:4:5) comes up on standardized tests a lot, so it is a good idea to memorize those ratios.

Answer 2

It is x, where x^2 + 12^2 = 13^2. This is actually an application of the Pythagorean theorem, where the diagonal is the hypotenuse.

x^2 + 12^2 = 13^2
x^2 + 144 = 169
x^2 = 25
x = 5

Answer 3

since it is a rectangle, there would be right angle the diagonal^2 = Length^2+Width^2

13^2 = 12^2 + Width^2
169 = 144 + Width^2
169-144 =Width^2
25 = Width^2
Width = 5 feet

Answer 4

Poor you!, this is no question to waste 5 points on, but quite good for earning 2 quick points. Threfore, your answer is sqrt(13^2 - 12^2) = sqrt(169 - 144) = 5

Answer 5

5 feet

144+ w2= 169
w2=25
w=5

Answer 6

So you have a triangle that has a leg 12 ft and one 13ft?
a2 + b2 = c2
144 + b2 = 169
b2 = 25
b=5

Answer 7

You should learn how to do your homework now b/c when it comes time for the test you wont have a computer

Answer 8

5
five