Find the distance between the two points given. Round to the nearest tenth, if necessary. (1,3) and (1,5)?

Question

A. 1.8
B. 2
C. 2.2
D. 4

Answer 1

B)2

Answer 2

you could simplify issues like this in case you subtract the comparable numbers from specific coordinates. you could subtract 4 from the x-coordinates, turning (4, 0) and (6, 3) into (0, 0) and (2, 3) The distances between (0, 0) and (2, 3) AND (4, 0) and (6, 3) often is the comparable the gap between(0, 0) and (2, 3) would be squareroot(2^2 +3^2) =squareroot(4 +9) =squareroot (13) approx 3.6

Answer 3

B is the right answer. As you can see, (1, 3) and (1, 5) are in a vertical line and the distance is 5 - 3 = 2

The general formula of distance bewtween two points (x1, y1) and (x2, y2) is given by

sqrt[(x2 - x1)^2 + (y2 - y1)^2]

and in this case, x2 - x1 = 0 and y2 - y1 = 2

Answer 4

B. (2), if you place the points on a coordinate plane you will see that point (1,5) is exactly 2 spaces above (1,3).

Answer 5

b

Answer 6

b