factorize this sum:
xy^5 - x^5y
It will be easier for me if u answer it with this formula:
a^2 - b^2 = (a+b)(a-b)
2007-08-06 02:59:35 · 6 answers · asked by Niranjana S 2 in Science & Mathematics ➔ Mathematics
take coomon///in
xy^5-x^5y ie
= xy(y^4 - x ^4)..............taking (a^2 -b^2)..if a =y^2..b =x^2
= xy(y^2+x^2)(y^2-x^2)
= xy(same)(y+x)(yix)//
i hope u got it sweety..
cheers!
2007-08-06 03:14:15 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The product of two consecutive even integers is 168 and the numbers are 12 and 14 the sum of four consecutive intigers is -106 and the numbers are -25, -26,-27 and -28 The sum of four consecutive even inegers is -100 and the numbers are -22, -24, -26 and -28.
2016-05-19 21:12:22 · answer #2 · answered by kathleen 3 · 0⤊ 0⤋
Been a while since I've done any of these, but do you mean:
xy (x^2 + y^2) (x - y)(x + y)
Scratch that. Everyone else has done it already.
2007-08-06 03:25:52 · answer #3 · answered by Anonymous · 0⤊ 1⤋
x y^5 - x^5 y
= xy(y^4 - x^4)
= xy (y² - x²) (y² + x²)
= xy (y - x) (y + x) (y² + x²)
2007-08-06 03:25:19 · answer #4 · answered by Como 7 · 1⤊ 0⤋
x*y+5-x+5*y that is what they mean i no that and i am in 7th grade
2007-08-06 03:09:01 · answer #5 · answered by Allie 2 · 0⤊ 0⤋
take xy common
=xy(y^4-x^4)
=xy(y^2+x^2)(y^2-x^2)
=xy(y^2+x^2)(y+x)(y-x)
2007-08-06 03:14:47 · answer #6 · answered by shubham_nath 3 · 0⤊ 0⤋