Physics: Force calculations, what formula(s) are needed to calculate the force needed to propel and object?

Question

with the mass of .6 grams at 625 feet/second. I need formulas here people I am going crazy.

Answer 1

This is very simple. All you have to do is apply any amount of force and then calculate how long you need that force applied until you get the object to reach the velocity = 625 feet/second.
The equation of motion we need is:
F = ma
Mass = 0.6 gram or 6*10^-4 kilogram
We need to apply a force that would make the velocity of the object =625 feet/second or 187.6 meter/second, after which the force will be removed and the object will continue to travel with the speed desired.

V = V zero + a*t let a = 100 m/second^2
Vzero = 0. The object starts to move from 0 velocity.
187 = 100*t or t =1.87 second
F = 6*10^-4 * 100 = 6*10^-2 = 0.06 Newton
Applying 0.06 Newton for only 1.87 will result in causing the object to move to a velocity = 187 m/s or 625ft/second
Since you have no other impeding or resistive forces acting on the object, then it will continue to move with this velocity forever unless you apply a force to change the status of its inertia
So you need a force equal 0.06 Newton applied on the object with a mass equal to 0.6 grams for 1.87 seconds to cause it to move to a velocity = 625 ft/s or 187 m/s

Answer 2

The rigidity that strikes the yo-yo up the string comes from friction of the string against the axle. With the string held loosely, that rigidity isn't adequate to enhance the yo-yo because of the fact the friction rigidity is given via Fr1 = µ*m*g the place µ is the coefficient of friction of the string against the axle, m is the mass of the yo-yo. once you observe an upward rigidity of Fh jointly with your hand, the frictional rigidity will become Fr2 = µ*(Fh + m*g) If Fr2 > than the burden of the yo-yo, the yo-yo will climb the string µ*(Fh + m*g) > m*g Fh + m*g > m*g/µ Fh > m*g*(a million/µ - a million) while you could surely weigh the yo-yo to locate m*g, it is not elementary to locate µ. besides the fact that, you ought to use a spring scale (like a fish-weighing scale) to be certain how lots Fh is mandatory to basically initiate the yo-yo upward push, and that way you could calculate µ.

Answer 3

Which direction ???????