2007-08-05 22:54:55 · 4 answers · asked by ♥jazzy♥ 3 in Science & Mathematics ➔ Astronomy & Space
Using the inverse square law, as above, and Mars semimajor axis instead, which is 1.523 AU, you get the figure 43%. So, on average, a point in space at that distance from the sun gets 43% of the sunlight a point at 1 AUs distance gets. But neither earth or Mars are mere points. Earths atmosphere reflects and absorbs 20 to 70% of the sunlight. Putting that into the equation and considering that Mars hardly has an atmosphere at all it is quite feasible that Mars on occasion can get more sunlight per m^2 than earth... But the composition of that sunlight would be vastly different than what we are used to as it is mainly tha dangerous wavelenghts, such as UV and X-rays, that are absorbed by our atmosphere.
2007-08-06 01:44:26 · answer #1 · answered by DrAnders_pHd 6 · 1⤊ 0⤋
the distance of mars for the sun is: 1.6 AU and the distance of earth from the sun is 1 AU we know that the sunlight which a planet gets have a opposite relation with R^2 (R is the distance) so 1^2/1.6^2=0.39 so the percentage is 39 %
2007-08-06 01:00:50 · answer #2 · answered by suerena 2 · 2⤊ 0⤋
Both the above answers are correct. Since the orbit of Mars is quite elliptical, the distance varies quite a bit during the Martian year.
2007-08-06 03:33:15 · answer #3 · answered by campbelp2002 7 · 0⤊ 0⤋
Put it this way you will not be sun bathing there anytime soon
2007-08-05 22:59:03 · answer #4 · answered by Anonymous · 0⤊ 0⤋