Find all four digit numbers which are a complete square and in which the first two digits and last 2 are equal

Question

Well this is a question for maths and I need help. We are allowed to help others. IF you can help me get the answer, I need to know how you got it! Thank you!

Answer 1

The only integers when squared give 4 digit numbers are 32 through 99. Of these none (zero) have the first two digits and last two digits equal. The first integer squared with the first 2 and last digits the same was:
876^2=767376

I did it on a spread sheet (Excel) and looking at the square of integers > 31; i.e., 32, 33, 34, 35, 36...
That only took a few minutes.

Try it:
A1 = 32; B1= A1^2
A2= A1+1; B2 = B2^2
Then copy A2 and B2 to A3 through A900 and
B3 through B900

It was quicker than writing a program in basic to:
1. starting at 32 and ending at 1000 square the integer
2. Convert the interger value to characters
3. If Left 2 characters = Right 2 characters print number.

Answer 2

88^2 = 7744

Answer 3

dude... its 7