Is y=[(x^2)-2x-3]/x-3 a function? Please give its domain, range, axis of symmetry, and shape of graph, if it is so.
thank you
2007-08-05 16:40:03 · 4 answers · asked by rock-onz 1 in Science & Mathematics ➔ Mathematics
y = (x^2 - 2x - 3) / (x - 3) is inded a function. Its domain is all real x except x = 3, which would result in division by zero because x - 3 = 0 when x = 3. Apart from that value, where y is undefined, y is equivalent to x + 1, so the range is all real numbers. The function is a line with a point discontinuity at (3, 4), and there is no axis of symmetry.
2007-08-05 16:44:13 · answer #1 · answered by DavidK93 7 · 1⤊ 1⤋
Yes it is a function, now finish your math homework by reading what domain, range, axis of symmetry, is. Then plot the graph by giving values to x and solving for y. It is better if you learn how to solve this by studying and not having someone do it for you Mr. or Mrs. Hunk.
2007-08-05 23:56:14 · answer #2 · answered by hal 2 · 0⤊ 0⤋
yes it is. domain N except fot x=3
range: -1 to 3
axis of symmetry: x=1
2007-08-05 23:49:21 · answer #3 · answered by alwayss_ready 3 · 0⤊ 0⤋
(x - 3)(x + 1)
----------------
x - 3
y = x + 1
D = { All real numbers except 3}
R = { All real numbers}
no axis of symmetry
the graph is a straight line
2007-08-05 23:45:47 · answer #4 · answered by Anonymous · 0⤊ 1⤋