The odds of correctly guessing the each card is 1/52, so the odd of guessing four in a row is (1/52)^4 = 1/7311616. This assumes the card is replaced and the deck is reshuffled each time. If the cards are not replaced, it is instead (1/52)(1/51)(1/50)(1/49) = 1/6497400, because there is one fewer card in the deck for each drawing.
2007-08-05 15:41:31
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answer #1
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answered by DavidK93 7
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It depends whether you mean:
(1) The first four cards in a row without replacement.
(2) The first four cards in a row with replacement and shuffling.
(3) Any four sequential cards while going through the deck guessing each one.
All three answers are different.
(1) is 1 in 52*51*50*49.
(2) is 1 in 52*52*52*52.
(3) is pretty complicated, though far more likely if you have a good memory for cards already seen.
2007-08-05 15:43:23
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answer #2
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answered by McFate 7
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1/52 * 1/51 * 1/50 * 1/49 = 1 / 6497400 = .0000001539
It seems reasonable to assume that this is without replacement.
2007-08-05 15:51:05
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answer #3
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answered by Skeptic 7
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the odds of each correct guess = 1/# of cards
so four correct guess
= (1/52)(1/51)(1/50)(1/49)
= 1/6497400
= 1.53907716932927 x 10^{-7 }
2007-08-05 15:58:47
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answer #4
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answered by vlee1415 5
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ZERO for the average person...100% for a magician...or card shark.
2007-08-05 15:52:52
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answer #5
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answered by grannycats100 2
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1:6,497,400...without replacement
1:7,311,616...with replacement
2007-08-05 15:40:42
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answer #6
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answered by Tech3SurfMan 2
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