English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Formula:
-b +/- √b²-4ac / 2a

prob.
x²+6x-4=0
plug values.

1) -6 +/- √36-4*1*-4
2) -6 +/- √52

I retry. Complete Square way.

(x+6/4)²-36/16=4 +36/16
(x+3/2)²=100
\ect...Which will turn out different. BS.

God SMACK this is G@y.
Damn. Help, Quadratic are so stupid shyt. Can't even solve this. Damn.itt

2007-08-05 14:52:46 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

You forgot to divide by 2a, which would be 2

So it's -3 +/- sqrt 13

(since sqrt 52 = sqrt (4 X 13) = 2 sqrt 13

2007-08-05 15:00:25 · answer #1 · answered by hayharbr 7 · 1 1

Looks like you also have problems with word definitions. An equation is not dumb. It just sits there waiting for someone to solve it. Some people see it faster than others, that's all. And Einstein was quite the ladies' man, believe me (wives and mistresses). So I do not see the link with solving equations and one's orientations.

The formula, written more clearly (using lots of brackets):

{ -b +/- SQRT[ b^2 - (4*a*c) ]} / 2a

when the quadratic is written as
a*x^2 + b*x + c = 0

In
x²+6x-4=0
You have a = 1, b = 6, c = -4
(note that c has a negative value)
{-6 +/- SQRT[36 - (-16)]}/2
{-6 +/- SQRT[36+16]} / 2
Distributing the division by 2:
-6/2 +/- (1/2)*SQRT(52)
-3 +/- (1/2)*SQRT(52)
52 is 4*13;
the square root of a product is the product of the square roots:
-3 +/- (1/2)*SQRT(4*13)
-3 +/- (1/2)*SQRT(4)*SQRT(13)
SQRT(4) is 2; 2 times 1/2 is 1:
-3 +/- (1/2)*2*SQRT(13)
-3 +/- SQRT(13)

So, one root is -3 + √13
and the other is -3 - √13.

-----

Completing the square:

x²+6x-4=0
add 13 to both sides:
x²+6x-4 +13 = 0 +13
x²+6x+9=13
(x+3)² = 13
root both sides

x + 3 = +/- √13
x = -3 +/- √13

2007-08-05 22:17:56 · answer #2 · answered by Raymond 7 · 0 0

Formula
x = [- 6 ± √(36 + 16)] / 2
x = [- 6 ± √52 ] / 2
x = [- 6 ± 2√13] / 2
x = - 3 ± √13

Completing square
x² + 6x = 4
x² + 6x + 9 = 4 + 9
(x + 3)² = 13
x + 3 = ± √13
x = - 3 ± √13

2007-08-06 03:40:40 · answer #3 · answered by Como 7 · 0 0

x²+6x-4=0


-b ± (√b²-4ac) / 2a

- 6 ± (√6²-4(1)(-4)) / 2(1)

First...

- 6 + (√6²-4(1)(-4)) / 2(1)
-6 + (√36+16)/2
-6 + (√52)/2
-6 + (2√13)/2
-6 + √13 ---> First answer

Second..

-6 - (√36+16)/2
-6 - (√52)/2
-6 - (2√13)/2
-6 - √13 ---> second answer

2007-08-05 22:08:50 · answer #4 · answered by roOt 3 · 0 0

x^2 + 6x +? -? -4 = 0
(X+3)^2-9-4=(X+3)^2-13
(X+3)^2=13

(X+3) = +/- sqrt(13)
X = -3 +/- sqrt (13)

2007-08-05 22:03:55 · answer #5 · answered by telsaar 4 · 0 0

try (-6 +/- (52)^0.5)/2

You left out the part about divided by 2a.

2007-08-05 22:00:35 · answer #6 · answered by Tom K 6 · 0 1

fedest.com, questions and answers