plz help me solve these questions ty?

Question

plz show your work and steps
ty
1) A dog walks at a speed of 1.8m/s along the deck toward the front of a boat that is traveling at 6.6m/s with respect to the water. What is the velocity of the dog with respect to the water? Wat if the dog were walking toward te back of the boat?
2) A vacationer walks 4km/h directly across a cruise ship whose speed relative to the earth is 13.2km/h. What is the speed of the vacationer with respect to the earth?
3)Two trains approach each other on parallel tracks. ach has a speed of 80km/h with respect to the earth. If they are initially 10km apart, how long will it be before they pass each other?

Answer 1

1. let the dog's speed be v and the boat's speed be vb. Since the dog and the boat move together, the total speed is:

vt = v + vb = 1.8 + 6.6 = 8.4 m/s

2. Let the vacationer's speed be vc and the boat's be vb. Since the two are directed at right angles to each other, they add according the Pythagorem theorem:

vt = sqrt(vc^2 + vb^2) = sqrt(4^2 + 13.2^2) km/hr

3. The two trains move at the same rate but in opposite directions so they have to meet when each train has travelled 5km. So

5 km = 80 km/h * t ---> t = 5/80 hrs = 1/16 hrs

Answer 2

1. let the dog's speed be v and the boat's speed be vb. Since the dog and the boat move together, the total speed is:

vt = v + vb = 1.8 + 6.6 = 8.4 m/s

2. Let the vacationer's speed be vc and the boat's be vb. Since the two are directed at right angles to each other, they add according the Pythagorem theorem:

vt = sqrt(vc^2 + vb^2) = sqrt(4^2 + 13.2^2) km/hr

3. The two trains move at the same rate but in opposite directions so they have to meet when each train has travelled 5km. So

5 km = 80 km/h * t ---> t = 5/80 hrs = 1/16 hrs

Take care
Bye

Answer 3

give me 5 mins ill try to do it