You have a square, but on the top of the square you have a extra little edge. The measurements of the whole thing are 15ft by 15ft at the top where you have the extra part and the the rest of the square is 40ft by 50 ft. How would you find the area for this weird square?
2007-08-05 08:52:27 · 6 answers · asked by thecookfamily00 1 in Science & Mathematics ➔ Mathematics
yes this is a hard one to explain. It is on my math test and I do not know how to show it.
2007-08-05 09:00:08 · update #1
if i can email anyone my test i will so maybe that will help...
2007-08-05 09:03:35 · update #2
Hello Now im all cofuseded Drooollllllll
2007-08-05 08:55:38 · answer #1 · answered by Danny Eire 2 · 0⤊ 0⤋
A square is usually a by a like you have said 15ft by 15ft.
The 40ft by 50 ft is no longer a square but a rectangle.
Since no picture is given I'll foolishly guess and assume that you are looking for an area of one less the area of the other.
A=A1-A2= 40x50 - 15x15=2000 - 225=1775 ft^2
2007-08-05 15:59:39 · answer #2 · answered by Edward 7 · 0⤊ 0⤋
the rest of the square is 40ft by 50 ft
how any square can have such dimensions.
2007-08-05 15:59:49 · answer #3 · answered by samu 1 · 0⤊ 0⤋
Sorry. Your explanation seems to desribe an impossible situation. Try explaining this a little better.
2007-08-05 15:58:53 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
Draw a picture and put a link to it.
2007-08-05 15:58:30 · answer #5 · answered by Jeƒƒ Lebowski 6 · 0⤊ 0⤋
40x50=2000<>>>>>>IS<>>>>>>
2007-08-05 15:58:18 · answer #6 · answered by THE"IS" 6 · 0⤊ 0⤋