Find the derivative of f(x)= sin (tan^-1(x/2))?

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2007-08-05 08:46:31 · 2 answers · asked by chimstr 1 in Science & Mathematics ➔ Mathematics

what would it be in the form of (x^2+4)^(3/2) in the denominator?

2007-08-05 09:04:17 · update #1

The derivative is 4/((x^2+4)^(3/2)). I'm assuming that you mean Arctan when it's shown as "tan^-1".

2007-08-05 09:12:46 · answer #1 · answered by Scythian1950 7 · 0⤊ 0⤋

f'(x) = cos(tan^(-1)(x/2)) (d/dx)(tan^(-1)(x/2))
= cos(tan(-1)(x/2)) (1/2) / ( (1/2)^2 + x^2 )
= 2cos(tan(-1)(x/2)) / (1 + 4x^2).

2007-08-05 15:57:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋