Which of the following is an equation for the tangent plane to the surface x^2 + 2y^2 + 3z^2 =6 at (1,1,1)?

1 ⤊

Which of the following is an equation for the tangent plane to the surface x^2 + 2y^2 + 3z^2 =6 at (1,1,1)?

possible equations.....

x + 2y + 3z = 6
4x + y + 6z = 21
x + 3y + 2z = 11
3x + y + z = 14
4x + 4y + 3z = 19
3x + 4y + 3z = 14
or is it none of these?

2007-08-05 08:03:04 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2 answers

I think the answer is c

2007-08-05 08:06:43 · answer #1 · answered by Anonymous · 0⤊ 1⤋

3z^2= 6-x^2-2y^2
6z*dz/dx=-2x so dz/dx = -2x/6z
6z dz/dy= -4y so dz/dy= -4y/6z
At(1,1,1)
z-1=-1/3(x-1)-2/3(y-1)
3z-3 =-x+1-2y+2 so x+2y+3z=6(the first)

2007-08-05 08:27:48 · answer #2 · answered by santmann2002 7 · 1⤊ 0⤋