6Sin²Θ - 5SinΘ + 1 = 0?

0 ⤊

Solve For Θ

0 ≤ Θ < 360

2007-08-05 06:32:49 · 2 answers · asked by Bobby R 2 in Science & Mathematics ➔ Mathematics

(3 sin θ - 1) (2sin θ - 1) = 0
sin θ = 1 / 3 , sin θ = 1 / 2
θ = 19.5° , 160.5° , 30° , 150°

2007-08-05 06:40:43 · answer #1 · answered by Como 7 · 0⤊ 0⤋

It's a quadratic equation in sin theta. Solve as you would normally solve a quadratic.

2007-08-05 06:38:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋