2007-08-05 06:13:42 · 5 answers · asked by Mercedes 1 in Science & Mathematics ➔ Mathematics
3xy + 1 = 2y - 5x
3xy - 2y = -5x - 1
y(3x - 2) = -5x - 1
y = (-5x - 1)/(3x - 2)
2007-08-05 06:19:24 · answer #1 · answered by math_gives_headache 2 · 0⤊ 0⤋
Get both terms having a y in them on the same side of the equal sign and all other terms on the other by subtracting a 2y +1 from both sides (or adding -2y-1 which is the same result. This produces 3xy-2y = -5x-1 then factor out the y on the left side to get y(3x-2) = -5x-1. Then divide through the equation by 3x-2 ( or multiply by 1/(3x-2)). You are left with y=(-5x-1)/(3x-2) which may be written alternately as -(5x+1/(3x-2) or as (5x+1)/(2-3x)
2007-08-05 13:29:47 · answer #2 · answered by chasrmck 6 · 0⤊ 0⤋
2y - 3xy = 5x + 1
(2 - 3x) y = 5x + 1
y = (5x + 1) / (2 - 3x)
2007-08-05 13:26:01 · answer #3 · answered by Como 7 · 0⤊ 0⤋
its going to look something like this
3xy+1=2y-5x
-2y -2y
__________________
3xy+1=-5x<
-2y +1=-5x < Will be ur answer.
3xy over -2y is how it should look at the top
2007-08-05 13:21:58 · answer #4 · answered by Hi 2 · 0⤊ 0⤋
3xy + 1 = 2y - 5x // -2y
3xy - 2y + 1 = -5x // -1
3xy - 2y = -5x -1
(3x - 2)y = -5x-1 // divide by 3x-2
y = (-5x - 1)/(3x - 2)
It will look better as:
y = (5x + 1)/(2 - 3x)
2007-08-05 13:19:58 · answer #5 · answered by Amit Y 5 · 0⤊ 0⤋