The length of a rectangle is 3 in. more than twice its width. If the perimeter of the rectangle is 36 in., find the width of the rectangle.
2007-08-05 05:35:54 · 7 answers · asked by trevor s 2 in Science & Mathematics ➔ Mathematics
Let x = width, 2x + 3 = length.
Equation:
2(x + 2x + 3) = 36
2(3x + 3) = 36
6x + 6 = 36
6x = 36 - 6
6x = 30
x = 30/6
x = 5
Answer: 5 is the width of a rectangle.
Proof:
2(5 + [2{5} + 3]) = 36
2(5 + [10 + 3]) = 36
2(5 + 13) = 36
2(18) = 36
36 = 36
2007-08-09 05:13:40 · answer #1 · answered by Jun Agruda 7 · 2⤊ 0⤋
The width = w
The length = 2w + 3 (twice the width plus 3)
To get the perimeter (add up all 4 sides), use:
w+w+2w+3+2w+3 = 36
So 6w + 6 = 36 (I combined the like numbers)
-6 -6 (subract 6 from each side to isolate the w)
6w = 30 (divide each side by 6 so you get w alone)
w = 5
length = 13 (2x5 plus 3)
2007-08-05 12:44:37 · answer #2 · answered by Celestial 2 · 0⤊ 0⤋
P = Sum{rectangle sides}
P = 3 + x
but P= 36 in
36 = 3 + x
x = 33 in
2007-08-05 13:29:07 · answer #3 · answered by Gearld GTX 4 · 0⤊ 0⤋
Let width be W and length be L
L = 2W + 3
P = 2L + 2W
36 = 2(2W + 3) + 2W
36 = 6W + 6
6W = 30
W = 5
Width = 5 inches
2007-08-05 13:47:11 · answer #4 · answered by Como 7 · 0⤊ 0⤋
36 = L + W + L + W
36 - 6 = 30
30/6 = 5
L = 5
W= 30
36 = 5 + 13 +5 + 13
2007-08-05 13:24:07 · answer #5 · answered by DesTynee J. 2 · 0⤊ 0⤋
(2)(2w+3)+2w=36
4w+6+2w=36
6w+6=36
6w=30
w=5
width is 5 inches
length is 13 inches
2007-08-05 12:41:05 · answer #6 · answered by Cheeseman 2 · 0⤊ 0⤋
(l-3) = 2w
2*(l-3)+2*(2w)=36
We have two problems and two equations, solve for both l and w.
2007-08-05 12:47:25 · answer #7 · answered by eric l 6 · 0⤊ 0⤋