2007-08-05 05:35:23 · 8 answers · asked by jirvine7774 1 in Science & Mathematics ➔ Mathematics
No it's 1 to 36, not 1 to 38, or 0 or 00. Trust me, I've lost money playing it.
So there are 38 different slots on the wheel.
The probability of it landing on a specific number is 1/38 assuming the wheel is a fair wheel (ie the probability the ball lands in a slot is the same for each slot).
1/38 = 0.0263
So there's a 2.63% chance of landing on 7.
2007-08-05 05:39:09 · answer #1 · answered by whitesox09 7 · 1⤊ 0⤋
HI SFMaster There are 18 even numbers other than 0 and 00 out of 38 numbers So P = 18/38 = 9/19 Shy
2016-05-19 04:04:33 · answer #2 · answered by shelia 3 · 0⤊ 0⤋
Probability would be 1 in 40 that it would stop on 7. But I think that a roulette wheel goes only to 36. So, then the odds would be 1 in 38.
: )
(I like black 24 - lol)
2007-08-05 05:38:52 · answer #3 · answered by anicoleslaw 5 · 1⤊ 1⤋
Those who say that a standard roulette wheel has 1 to 36 are correct. Some casino's still use the wheel that has only 1 Zero in one slot, so there are only 37 slots on that wheel. It is obviously the best wheel to play because the chances of loosing to Green 0 are cut in half.
2007-08-05 05:58:36 · answer #4 · answered by Downeasta 2 · 0⤊ 0⤋
If it really has those numbers 0-38 plus double zero then there are 40 equally probable stopping points. So the odds of 7 are 1 out of 40.
2007-08-05 05:43:33 · answer #5 · answered by Rich Z 7 · 1⤊ 0⤋
1/40
2007-08-05 05:42:19 · answer #6 · answered by Cheeseman 2 · 0⤊ 1⤋
40 equally probable outcomes so the answer is 1/40
2007-08-05 05:39:07 · answer #7 · answered by rscanner 6 · 0⤊ 1⤋
One in fourty.
2007-08-05 05:40:50 · answer #8 · answered by eric l 6 · 0⤊ 1⤋