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solve the following equations for y'

a. xy' + y =1+ y'
b.2x + 2xy' + 2y + 3y^2y' = 0
c.x/y' + y = 5/y'

please please help

2007-08-05 03:30:51 · 1 answers · asked by dingdong 1 in Science & Mathematics Mathematics

1 answers

a. xy' + y =1+ y'
y'(x-1)=1-y

y'=(1-y)/(x-1)

b.2x + 2xy' + 2y + 3y^2y' = 0
y' (2x+3y^2)=-2x-2y

y'=(-2x-2y)/(2x+3y^2)


c.x/y' + y = 5/y'

(1/y') (x-5)=-y

1/y'=-y/(x-5)

y'=(x-5) / -y

2007-08-05 03:36:56 · answer #1 · answered by iyiogrenci 6 · 0 0

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