Which of the following organic compounds is probably the most reactive?

Question

a. C2H6
b. C3 H8
c. C2H2
d. C4 H10

Could you explain how u detemine a compound to be the most reactive?

please the numbers they are subscripts

Answer 1

The structure of these compounds is :
H H
I I
C2H6 or H- C-------C - H
I I
H H



C3H8 or H3C-CH2 - CH3;


C2H2 or HC =_ CH;



C4H10 or H3C- CH2 - CH2 -CH3


Here only C2H2 (Acetylene ) is having unsaturated carbon atoms which is why it will be most reactive .
All others are saturated hydrocarbons actually paraffins

Answer 2

There are many ways to explain the reactivity and probably we could have several answers with respect to what will react with the given organic compounds (alkene: C2H2-ethene/acetylene; alkane: C2H6 -ethane, C3H8 -propane, C4H10 -butane). In the given we have alkane and an alkene(unsaturated hydrocarbon).
Considerations:
1. The alkanes will have substitution reaction (SN1, SN2, or free radical substitution) and will not do for the given alkene.
Decreasing reactivity
SN1: butane>propane>ethane
SN2: ethane>propane>butane

2. Complete Combustion (reaction with O2 in air)
Hydrocarbons are very reactive due to combustion in O2 in air. The reaction usually result to fire. Though it is hard to determine how fast the reaction because it's too rapid determine. But take this into consideration that the reactivity of hydrocarbon with O2 is proportional to the number of bonds in the hydrocarbon to be broken or oxidized by O2 to form carbon dioxide and water. Thus, hydrocarbon that has most numbers of bonds will take higher time to oxidized and that least reactive.

Decreasing reactivity: Ethene>ethane>propane>butane

Does these explanations make sound to you?

Answer 3

Acetylene (c) is the most reactive (least stable) because the tendency of carbon atom bonds to be tetrahedral is most distorted in this molecule. The molecule will willingly donate a proton in a strong base environment such as sodamide in liquid ammonia to afford sodium acetylide. In a. (ethane) the bonds are almost perfectly tetrahedral and the molecule is strain free. The protons are not significantly acidic. B is propane, another paraffin with all single bonds and, again, it's almost strain free as is d (butane). However, in this molecule there are a couple of isomers but all are paraffins and there is little strain. But, the tertiary butane isomer of d would be the next most reactive since its methyne proton demonstrates some acidic tendencies similar to acetylene.

Answer 4

If a compound is an aliphatic hydrocarbon , such in this case, shorter the carbon chain more reactivity exist. another factor is the insaturation grade, a compound is more reactive if contain multiple bonds,so if it has triple bounds will be more reactive that one with double or simple bound, then the most reactive is acetylene ,C).
P.D. excuse my English.

Answer 5

The answer is "c" C2H2

The other compounds are saturated hydrocarbons called alcanes (general formula CnH(2n+2)) They are all stable ,whereas C2H2 acetylene has a triple bound very reactive

Answer 6

I would say C2H2 !!!!!!!!!! Hope it will help !!!!!!!!