2007-08-04 21:52:37 · 7 answers · asked by nestly7 1 in Science & Mathematics ➔ Mathematics
Hi,
4x + 20
----------- factors into
x² - 25
4(x + 5)
-----------------
(x - 5)(x + 5)
The (x + 5) factor cancels out, leaving:
4
------
x - 5
I hope that helps!! :-)
2007-08-04 21:59:56 · answer #1 · answered by Pi R Squared 7 · 0⤊ 0⤋
Solve, in lowest terms:
(4x + 20)/(x^2 - 25)
Since the denominator,
(x^2 - 25) = (x + 5)(x - 5)
We have ,
(4x + 20)/[(x + 5)(x - 5)
= 4(x + 5)/[x + 5)(x - 5)]
= 4/(x - 5)
2007-08-04 22:07:10 · answer #2 · answered by ideaquest 7 · 0⤊ 0⤋
The solution is 4 / x-5
Here is how......
4x + 20 / x^2 - 25
= 4(x + 5) / (x+5)(x-5) [Difference of two Squares!]
= 4 / x - 5 [Cancelling out (x + 5)
Hope it Helps!
2007-08-04 22:01:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
4x+20 = 4(x+5) and x^2-25 = (x-5)(x+5)
so 4x+20/x^2-25 = 4(x+5)/(x+5) (x-5)
answer 4x+20/x^2-25 = 4/(x-5)
2007-08-04 22:02:33 · answer #4 · answered by maussy 7 · 0⤊ 0⤋
4x+20/ (x+5)(x-5)
4(x+5)/(x+5)(x-5)
= 4/(x-5)
2007-08-04 22:02:27 · answer #5 · answered by gab BB 6 · 0⤊ 0⤋
4(x+5)/(x-5)(x+5)=4/(x-5)
2007-08-04 22:10:38 · answer #6 · answered by Anonymous · 0⤊ 0⤋
factor
4(x + 5) / [ (x + 5) (x - 5)]
simplify
4 / (x - 5)
2007-08-04 22:02:28 · answer #7 · answered by 7 · 0⤊ 0⤋