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An electric field parallel to the surface of a conductor would imply a voltage difference accross the conductor, which would create a current, and therefore a non-static system. So your statement is correct.

2007-08-04 22:11:03 · answer #1 · answered by MooseBoys 6 · 0 0

Yeah, simply by fact the exterior of cost-allotted-(appropriate)conductor is equipotential we are able to continually have 0 ability gradient at tangents to the exterior, this actuality is obvious and universally conventional to counter-tutor the equipotential theory of (appropriate)attaining surfaces... be conscious the emphasise on (appropriate). properly basically for exciting sake enable us to locate the exterior at atomic point, if the fees are allotted gently throughout the time of each and each atom's electron shell then meaning that: (a) each and each atom is the two charged. (b) overruling the thermal agitation of atoms (different than at 0 Kelvin) they're the two allotted in the lattice. (c) there's no impurity in the lattice. (d) the test is performed in and remoted device in vaccum. then we would word here (attempt employing a comedian strip to devise the electrical powered fields and watch): (a) the electrical powered field brought about by means of guy or woman atoms nullify one yet another alongside the inter-atomic area- and for this reason until the tangent to the exterior, we have no resultant field.... TO BE talked approximately. (b) the electrical powered field in the area exterior the lattice is resultant of the entire vector sum of electric powered fields by means of each and every guy or woman atoms. simply by fact the lattice incorporates countless atoms (while in comparison with the infinitesemaly small field capability in touch), the process the consequent field is often perpendicular to the consumer-friendly-tangent to the atoms... TO BE talked approximately. now coming lower back to our component: the statements (a) and (b) above could recommend that there's no tangential field on the exterior of the lattice and that if there is a few resultant electric powered field, that's continually perpendicular to the tangent...

2016-11-11 06:31:56 · answer #2 · answered by ? 4 · 0 0

Yes.

2007-08-04 20:53:58 · answer #3 · answered by ag_iitkgp 7 · 0 0

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