cun u please solve this trigno numerical...........?

Question

16sin2x + 16cos2x = 10 find the value for x...........
that 2 is raied to the power i mean it is square.........

Answer 1

I think that equation is impossible:

We can factor out 16

16(sin²x + cos²x) = 10

Divide both sides by 16

sin²x + cos²x = 1/6

(But we have a trigo identity... sin²x + cos²x = 1)

So, no answer...

Answer 2

16sin2x + 16cos2x = 10

Let y=sin2x
then cos2x = sqrt( 1 - y^2 )
8cos2x = 5 - 8sin2x
8 (1 - y^2)^{1/2} = 5 - y
64 (1 - y^2) = (5 - y)^2 = 25 - 10y + y^2
65y^2 - 10y + 25 - 64 = 0
65y^2 - 10y - 39 = 0
sin2x = y = [ 10 +or - sqrt( 100 + 4(65)(39) ] / 130

Answer 3

sin^x+cos^2 x=5/8
divide each term by cos^2 x

tan^2 x +1=5/8

tan^2 x =-3/8

x= arc tan(-3/8)

or use your calculator

Answer 4

there is something wrong w/ ur problem :|