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How to derive rate-constant for a second order reaction when the concentration of reactants are are - (1)equal (2) unequal
Can you please derive it for me? It's an assignment & I just have 12 hours left.Please! Thanks!

2007-08-04 18:17:26 · 2 answers · asked by whatever 2 in Science & Mathematics Chemistry

2 answers

Let
aA >> Products a second order reaction.
The law is :
- 1/a d[A] / dt = k[A]^2
- d[A] / [A]^2 = kdt
1 / [A] - 1 / [A]° = k(t-t°)

Let
aA + bB >> products a secon order reaction
if a=b and [A] = [ B]
v = - d[A] / dt = k [A]^2
k = 1/t ( 1 / [A] - 1 / [A°]

if a = b = 1 and A is not equal B
v = - d [A] / dt = k [A] [B]

2007-08-05 01:45:33 · answer #1 · answered by Dr.A 7 · 0 0

The derivation contains many symbols which cannot be drawn here, better consult a text book.

2007-08-04 20:57:17 · answer #2 · answered by ag_iitkgp 7 · 0 0

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