f(t) = 4.5e^t
I have to find the domain and explain how I got it, problem is, I can't find an example in my book.. I am stumped.
2007-08-04 17:54:56 · 5 answers · asked by amber 3 in Science & Mathematics ➔ Mathematics
I also need help with this one:
g(x) = 2^x
2007-08-04 17:56:39 · update #1
In both cases the domain is all the real numbers.
For f(t)=4.5e^-t, t can take on any real value from - infinity to + infinity and the function remains continuous. If you were to plot the function or graph it on a calculator, you would see that it is a nice continuous curve. Same for 2nd question.
2007-08-04 18:08:58 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
f(t) = 4.5e^t
domain: all t where f(t) is defined
the domain is the whole real line (-infinity,+infinity)
2007-08-05 00:58:47 · answer #2 · answered by vlee1225 6 · 0⤊ 0⤋
plug in x or y values of any numbers you want (or in other words t or f(t) values) and notice the shape of the graph. then you will be able to observe the domain. Its simple to explain how you did it, too!
Good luck
2007-08-05 01:09:35 · answer #3 · answered by lightning 1 · 0⤊ 0⤋
I think the answer for both of them is that the domain is infinite.Remember, the domain for e^x is infinite, so multiplying it by a constant won't change anything.
2007-08-05 00:59:07 · answer #4 · answered by Anonymous · 0⤊ 1⤋
t and x are both greater than zero and go up to infinity
2007-08-05 01:03:46 · answer #5 · answered by Andy 2 · 0⤊ 0⤋