2007-08-04 13:58:27 · 3 answers · asked by lauren99999 1 in Science & Mathematics ➔ Mathematics
By using "log(a^b) = b * log(a)"
log(10^x) - log(10^2)
x * log(10) - 2 * log(10)
log (common log) of 10 is 1:
x * 1 - 2 * 1
x - 2
You can't solve to a specific solution unless there is an equals sign in there somewhere.
2007-08-04 14:02:19 · answer #1 · answered by McFate 7 · 0⤊ 1⤋
To solve for x, you must have the log set equal to something.
log 10^x - log 10^2
Use the power property
x * log 10 - 2 log 10
x - 2
If you set x -2 equal to whatever you're supposed to, you will be able to solve for x.
2007-08-04 21:03:01 · answer #2 · answered by Vu 3 · 0⤊ 0⤋
lg 10^x - lg 10^2 = x lg 10 - 2 lg 10
= x - 2
This expression can only be simplified but cannot be solved unless it is an equation.
2007-08-04 22:19:54 · answer #3 · answered by Anonymous · 0⤊ 0⤋