factor the ff?

4 ⤊

24 x^2 + 6 xy - 18 y^2

2007-08-04 13:36:25 · 3 answers · asked by CPUcate 6 in Science & Mathematics ➔ Mathematics

3 answers

24x^2+6xy-18y^2
=6(4x^2+xy-3y^2)
=6(4x^2+4xy-3xy-3y^2)
=6{4x(x+y)-3y(x+y)}
=6(x+y)(4x-3y)

2007-08-04 13:44:03 · answer #1 · answered by alpha 7 · 3⤊ 0⤋

the answer is 6(4x-3y)(x+y)

Here is how:

24x^2 +6xy -18y^2
= 6(4x^2 +xy - 3y^2)
= 6(4x^2 +4xy - 3xy -3y^2)
= 6(4x(x + y) -3y(x+y))
= 6(4x-3y)(x+y)

Hope it helps!

2007-08-04 13:45:51 · answer #2 · answered by Anonymous · 1⤊ 0⤋

(24x+y)(x-18y)

2007-08-04 13:41:53 · answer #3 · answered by 037 G 6 · 0⤊ 0⤋