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2007-08-04 13:23:09 · 4 answers · asked by CPUcate 6 in Science & Mathematics Mathematics

4 answers

y-[-y-y+1]
y+2y-1
3y-1

2007-08-04 13:30:53 · answer #1 · answered by Anonymous · 0 0

y-[y-(y-1)]
=y-[y-y+1]
=y-1

2007-08-04 20:27:12 · answer #2 · answered by alpha 7 · 1 0

y - [ - y - y + 1]
y + y + y - 1
=3y -1

2007-08-04 20:31:58 · answer #3 · answered by Anonymous · 0 0

y - [- y - y + 1] = y - [1 - 2y ] = 3y - 1

2007-08-05 06:13:28 · answer #4 · answered by Como 7 · 1 0

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