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on this equation


2(2x + 7)(2x + 3)


do you distribute the 2 first? or do you multiply the polynomials in parenthesis first? or what?

2007-08-04 12:29:19 · 7 answers · asked by Skyler 2 in Science & Mathematics Mathematics

7 answers

Either way. Remember that the order in which you do a series of multiplications *doesn't matter*

Might find it easiest to multiply the polys first, as if you don't, you have to remember to only distribute the 2 into one or the other poly.

2007-08-04 12:31:43 · answer #1 · answered by Anonymous · 1 0

Multiply in the parenthesis first PEMDAS is the order of operations

2(2x+7)(2x+3)

2(4x^2+14x+6x+21)
2(4x^2+20x+21)
answer 8x^2+40x+42

2007-08-04 20:43:24 · answer #2 · answered by Dave aka Spider Monkey 7 · 1 0

distribute the 2

2007-08-04 19:31:40 · answer #3 · answered by love♥shopping=] 3 · 0 0

Do as it fits you.

Proof:
2(2x + 7) (2x + 3)
(4x + 14) (2x + 3)
8x^2 + 40x + 42

2([2x + 7] [2x + 3])
2(4x + 20x + 21)
8x^2 + 40x + 42

Either way, the results are the same.

2007-08-08 06:43:34 · answer #4 · answered by Jun Agruda 7 · 2 0

I think it works either way. I think it's easier to distribute the polynomials in the parenthesis first! =)

2007-08-04 19:32:23 · answer #5 · answered by craz34jason 5 · 0 0

Here is how to do it.....

(2)(2x+7)(2x+3)

multiply 2 with both 2x+7 and 2x+3

so u get, (4x+14)(4x+6)
= 4x(4x+16)+14(4x+6)
= 16x^2 + 64x + 56x + 84
= 16x^2 + 120x + 84

hope it helps!

2007-08-04 19:34:43 · answer #6 · answered by Nick 2 · 0 1

find out what x equals.

2007-08-04 19:34:22 · answer #7 · answered by w00twednesday 3 · 0 0

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