find the time required for an object to fall to the ground from a building that is 1400 ft. high formula T=1/4suare root of 5
2007-08-04 11:53:26 · 4 answers · asked by vadataborn 2 in Science & Mathematics ➔ Mathematics
Acceleration due to gravity is 32 ft/sec, so use this equation:
s = -1/2 a*t^2 + v0 * t
Since it's dropped and not thrown upward, v0 (initial velocity) is zero, and can be left out. Also, you know that s = -1400 (1400 feet down), and a = 32 ft/s^2:
-1400 = -1/2 * 32 * t^2
-1400 = -16 t^2
t = sqrt(1400/16)
t = about 9.35 seconds
This ignores wind resistance, and I'm not quite sure what to make of "T = 1/4 sqrt(5)"
2007-08-04 11:57:40 · answer #1 · answered by McFate 7 · 0⤊ 0⤋
McFate's answer looks good to me!
If you wanted to be a smart "alec" (Rated G version) you could ask what the object is! If it was a clean sheet of paper (not crumpled) then it would fall straight down air resistance would cause it to sway around taking longer! Similar to a skydiver with a parachute!
2007-08-04 19:05:55 · answer #2 · answered by JimBob 6 · 0⤊ 0⤋
T = 1/4 * sqrt(5)? I don't really understand the formula but there is another way to solve
h = .5at^2
h = height
a = acceleration (32ft/s^2)
t = time in seconds
1400 = .5(32)t^2
1400 = 16t^2
t^2 = 87.5
t = 9.35s
2007-08-04 19:00:33 · answer #3 · answered by 7 · 0⤊ 0⤋
T = (5^.5)/4 is not a formula but a condition
can you please state what T is, i am assuming time
and can you provide a formula, you know with an independent variable and a dependent one.
2007-08-04 18:59:34 · answer #4 · answered by Anonymous · 0⤊ 0⤋