Multiply by 12 to remove denominators:
3 (2x - 3) < 4 (3x + 1)
Distribute the values and isolate x:
6x - 9 < 12x + 4
-13 < 6x
-13/6 < x (or x > -13/6)
2007-08-04 07:12:28
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answer #1
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answered by McFate 7
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Step one, get rid of the pesky fractions by multiplying both sides by 12. We get
3(2x - 3) < 4(3x + 1) Now distribute
6x - 9 < 12x + 4 Now simplify
-13 < 6x Now divide by 6
-13/6 < x
2007-08-04 07:47:37
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answer #2
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answered by dvc_dude_25 4
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Hi,
2x.-.3....3x.+.1
-------.<.---------
....4...........3
To eliminate fractions, multiply both sides by 12. Remember multiplying by a positive number does not change the inequality.
12(2x.-.3)....12(3x.+.1)
-------------.<.--------------
....4....................3
This reduces to:
3(2x.-.3)..<..4(3x.+.1)
Distribute to eliminate parentheses.
6x.-.9..<..12x.+.4
Subtract 12x and add 9 to both sides. Then simplify.
-6x < 13
Divide by -6. Remember that dividing by a -6 will reverse the inequality sign.
x > -13/6 <== answer
x > -2 1/6 <== answer as a mixed number
I hope that helps!! :-)
2007-08-04 07:10:07
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answer #3
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answered by Pi R Squared 7
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you will desire to have 3 solutions to this question a million. (2x-3) > 0 2x>3 x>3/2 2. 3x+4 > 0 3x >-4 x>-4/3 3. x-a million>0 x >a million x>a million If any of the contraptions in parenthesis are 0, then your finished equation is going to 0
2016-10-01 09:39:33
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answer #4
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answered by mcglothlen 4
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3(2x-3)<4(3x+1) (by multiplying through by denominators)
6x-9<12x+3 (by multiplying out brackets)
6x<12x+12 (by adding 9 to both sides)
-6x<12 (by taking 12x from both sides)
-x<2 (by diving by 6)
x>2 (swapping signs swaps the inequality)
you really should be asking your teacher if you don't get how to do these questions!
2007-08-04 07:12:59
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answer #5
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answered by DAN H 3
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(2x-3)/4<(3x+1)/3;
3(2x-3)<4(3x+1)
6x-9<12x+4
-13<6x;
x>-13/6
2007-08-04 07:12:09
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answer #6
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answered by chaveen 2
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Im not good at math lol
2007-08-04 07:08:19
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answer #7
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answered by Sweet_angel 3
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