4^1/5 * 4^7/10
Simplify!
2007-08-04 06:10:57 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Since the base is the same(4) you can add the exponents:
In general: x^a * x^b = x^(a+b)
Here: 4^1/5 * 4^7/10 = 4^(1/5+7/10) = 4^9/10
Now, since 4 is also 2^2, you can simplify even further:
In general: (x^a)^b=x^(a*b)
Here: 4^9/10 = (2^2)^9/10 = 2^(2*9/10) = 2^18/10 = 2^9/5
Simple, isn't it?
2007-08-04 06:17:36 · answer #1 · answered by Shadow 3 · 0⤊ 0⤋
4^1/5 * 4^7/10
= 4^2/10 * 4^7/10 = 4 ^ 9/10
= 2^9/5
2007-08-04 13:16:28 · answer #2 · answered by ironduke8159 7 · 2⤊ 0⤋
4^1/5 * 4^7/10
=4^(1/5 + 7/10) because x^a*x^b=x^(a+b)
=4^(2/10 + 7/10)
=4^9/10
2007-08-04 13:14:21 · answer #3 · answered by highlandcow 2 · 0⤊ 0⤋
With multiplication of same bases, you can just add the exponents.
So, you basically have 4^(2/10) * 4^(7/10)
Add the exponents and you get:
4^(9/10)
2007-08-04 13:15:30 · answer #4 · answered by Lilovacookedrice 3 · 1⤊ 0⤋
4^(1/5) * 4^(7/10)
4^((1/5) + (7/10)
4^((2/10) + (7/10))
4^(9/10)
(2^2)^(9/10)
2^(18/10)
2^(9/5)
2007-08-04 15:22:46 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
a^b * a^c = a^(b+c)
2007-08-04 13:17:52 · answer #6 · answered by Anonymous · 0⤊ 0⤋