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The standard model of a black hole is almost like a concaved plane making up the event horizon, with a singularity at the tip. But wouldn't gravity be pulling equally from all directions around the singularity? That is, to say, wouldnt it make more sense for a black hole to not have a single event horizon, but rather a spherical field of gravitational pull?

2007-08-04 04:45:06 · 4 answers · asked by Anonymous in Science & Mathematics Physics

I understand what an event horizon is. What im asking is this:

Why would a black hole pull from one direction in space more than another? Wouldn't it make more sense to pull from all directions simultaneously (creating a spherical field of gravitational pull instead of the "cone" that makes up the Event Horizon)?

2007-08-04 05:24:00 · update #1

Oh, and btw: thanks for any input

2007-08-04 05:26:27 · update #2

4 answers

Gravitational attraction is strongest at the surface of any mass, including a black hole. The event horizon has nothing to do with gravity, space is curved so tightly at the surface of a black hole light follows that curvature. Light has no mass it will always be trapped in this eternal loop, anything with mass will go through this event horizon into the black hole. It makes no sense what so ever that more than one event horizon would exist.

2007-08-04 05:14:51 · answer #1 · answered by johnandeileen2000 7 · 0 1

If I understand the question, you're assuming that the event horizon consists of a single point. It does not. The event horizon is shaped like a sphere (if the hole isn't rotating). Its radius is proportional to the mass of the black hole. For a black hole with the mass of the sun, the event horizon would be (if I remember correctly) a sphere about 3 km across.

2007-08-04 05:07:16 · answer #2 · answered by RickB 7 · 1 0

I'm not sure I understand your question. The event horizon of a black hole is the surface of a sphere. I don't see why the shell theorem wouldn't apply outside the black hole, assuming spherical symmetry.

Gravitational attraction is not necessarily strongest at the surface of a mass, see the note at the end of the referenced article.

2007-08-04 05:15:40 · answer #3 · answered by Frank N 7 · 1 0

try a laxative

2007-08-04 04:50:35 · answer #4 · answered by sea link2 4 · 0 1

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