Yes, you are helping me with my homework. Apparently no one else knows this. Thanks to all answers.
1. Find the value of the index:
f(x)= x^2 + 6x + 5
2. Find the y value.
3. Is the vertex found minimum or maximum
4. What are the zeros of this parabola
2007-08-04 04:40:37 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1. complete the square of this equation to get:
x^2 +6x+9-4 = (x+3)^2 - 4
1. V=(-3,-4)
2. y= -4 @ x=0
3. Vertex is a min
4. x^2 +6x+5 =0
(x+5)(x+1)=0
x= -5 x= -1
2007-08-04 05:13:23 · answer #1 · answered by 037 G 6 · 0⤊ 0⤋
Instead of index, I think you mean vertex.
You can complete the square to put this into the proper form.
x^2 +6x+5 = (x+3)^2 - 4
1. The VERTEX is (-3, -4).
2. The y value of the vertex is -4.
3. This parabola is concave up, so the vertex is a minimum.
4. (x+3)*(x+2) => zeros are x=-3, x=-2.
2007-08-04 11:59:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋