A 0.4 kilogram sample of Aluminum at 100 degrees Celsius is put into a container containing 0.5 kilograms of water at 20 degrees Celsius. Neglecting the small amount of energy absorbed by the container and knowing the specific heat of Aluminum 900 kJ/kg*C is and the specific heat of the water is 4186 kJ/kg*C answer the following question. Compared to the heat liberated by the aluminum, the heat absorbed by the water is…
2007-08-04 03:07:25 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The heat absorbed by water is equal to the heat lost by aluminium Let Tf be the final temperature
the heat lost by aluminium is
Q1= mc dt= 0.4*900* (Tf-100)
and heat received by water
Q2= 0.5*4186* (Tf-20)
we have Q1 = -Q2
0.4*900*(100-Tf ) = 0.5*4186*(Tf-20)
36000-360Tf= 2093Tf-41860
77860=2453Tf
so Tf =31.74°C
2007-08-04 03:25:12 · answer #1 · answered by maussy 7 · 1⤊ 0⤋