the radius of the earth's orbit around the sun(assumed to be circular) is 1.50 x 10 power of 8km, and the earth travels around this orbit in 365 days.
a)what is the magnitude of the orbital velocity of the earth, in m/s?
b)what is the radial acceleration of the earth toward the sun, in m/spower of 2?
c)repeats part (a) and (b) for the motion of the planet Mercury (orbit radius = 5.79 x 10 power of 7km, orbital period = 88 days?
2007-08-04 02:05:51 · 2 answers · asked by DiMaHaZiaF 1 in Science & Mathematics ➔ Physics
a) "Magnitude of velocity" is just a fancy word for "speed." Speed equals distance divided by time. The distance is the circumference of the circle (which, I'm sure you know, is 2π times the radius); and they give you the time (365 d), so just divide. That will give you the speed in "kilometers per day." Just convert that to m/s. (Hint: there are 1000 meters in a km; and 86400 seconds in a day.)
b) "radial" means the same as "centripetal," so they're asking for the centripetal acceleration. As I'm sure you've read in your book, the formula for centripetal acceleration is: "a = v²/r". They already gave you "r"; and you figured out "v" from the answer in part (a).
c) Same problem; just using different numbers.
2007-08-04 03:03:50 · answer #1 · answered by RickB 7 · 0⤊ 0⤋
Actually it is in 4 dimensions!
Not only is the earth orbiting around the sun...
The sun is orbiting around the galaxy,
The galaxy is hurling through space and...
It is all happening in the dimension of TIME!
.
2007-08-04 02:55:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋