find the area bounded by three circles tanget to each other, given that the radius of the circle is 5?

Answer 1

Sketch the equilateral triangle formed by joining the centers of the three circles. This triangle has base 10 and height 5√3.
It's area is 1/2bh = 5x5√3 = 25√3
We're going to subtract from this the three circular sectors, each having a central angle of 60 degrees.
3(1/6)(pix5^2) = 25pi/2
The subtraction becomes:
25√3 - 25pi/2 = 25(√3 - pi/2) = 4.031

Answer 2

The circle will touch the sq. on the middle component of each and every of the sq.'s components. So the area from one in all those factors to the component on the alternative side is comparable to the diameter of the circle and is the dimensions of the climate of the sq.. here radius = 3.5 for this reason diameter = 7, for this reason the component of the sq. is 7 x 7 = forty 9 . word which you have not given any contraptions for the dimensions of the radius so which you're able to provide the section elementary as forty 9. Strictly speaking it will be forty 9 sq. contraptions of length the place the unit of length is the comparable as that of the radius. that's somewhat a mouth complete. Your instructor could provide you extra marks for being mathematically incredible or only think of you're a smarty pants.

Answer 3

7.5