triangle applications....?

Question

please help...
in what objects can we see o apply figures of triangles? ...

Answer 1

Bridge Truss, crystals, buildings.

The tirangle is the most stable structure that you can make. All structures use triangles as some point to make a connection to make the structure stronger. For example when you build a house you use a sill plate and a top plate that are parallel and then add studs that go between them setting the height of the structure. The right angles formed between the studs and the top plate and sill plate are right triangles.

The triangle is to building like the word is to a book. They are that fundemental.

The most basic steel bridge structure uses triangluar trusses. Whenever a 90 degree connection is made, that is a right triangle so it is used more often then you can count.

Skyscrapers use cross supports to help provide resistance against the wind, the most common method is with triangluar bracing.

Answer 2

In objects having "a basic shape of tetrahedron" we can relate triangle applications!

It is 3-dinmensional application

Similar relations exist with in some atoms as well as interlinked celestial bodies!

A tetrahedron has four vertexes and "equal triangular faces" and a-cube perfectly accommodate a tetrahedron by touching "four out of 8 corners of said 3D cube"!

Awareness of Inter-relations like these helps to extend study of triangles from a 2D-plane to 3D-cube-space which widens related knowledge of ours!

Answer 3

2 or more triangles could compose rectangles and squares, volumes where they could perfectly fit-in in an airtight fashion, etc. if we talk of abstract objects. Concretely, there are pyramids, windows and window panes panes, Toblerone chocolate bars, etc. There's a lot more if one is resourceful enough to use the imagination.

Answer 4

tan 34 = d1 / 90 d1=90 tan 34 d2=90 tan 58 d1+d2=distance between deers 205ft Assuming ship 1 went 26 degrees east of due north: 30 mph * 3h =90 mi sin 26= x1 / 90 x1=90sin 26 yi=90cos26 Ship 2 went 32 degrees west of due north x2=90sin 32 y2=90cos26 d between them is sqrt( (x2-x1)^2 + (y2 - y1)^2) Note: using the distance formula you may get a negative cooeficient when subtracting. Dont worry when you square it the negative goes away. 9 miles

Answer 5

a gabled roof
finding area of any polygon with more than 4 sides (like an odd shaped parcel of land)
trigonometry
wings of many fighter jets
calculating the height of a mountain from the base

Answer 6

Molecules of water or ammonia.