2007-08-03 16:55:03 · 5 answers · asked by booboobear_619 1 in Science & Mathematics ➔ Mathematics
Using synthetic division, it can be shown that x - 5 is a factor:-
***|1****-5****2****-10
**5|*****5****0*****10
---------------------------
***|1****0****2*****|0|
-------------------------
Factors are (x - 5) (x² + 2)
2007-08-03 20:35:20 · answer #1 · answered by Como 7 · 2⤊ 0⤋
You can factor x³ - 5x² + 2x - 10 just by grouping:
First write: x³ - 5x² + 2x - 10 = (x³ - 5x²) + (2x - 10)
= x³(x - 5) + 2(x - 5) = (x - 5)(x³ + 2).
The expression in the second brackets cannot be further factorized. So above are the complete factors.
2007-08-03 17:02:01 · answer #2 · answered by quidwai 4 · 0⤊ 0⤋
It doesn't have GCF
get the first two and the last two
x^3 - 5x^2-------------------2x-10
get the GCF of each
x^2(x-5)---------------------------2(x-5)
x^2(x-5)+2(x-5)
=(x - 5)(x³ + 2)
2007-08-03 17:04:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(x²+2)(x-5)
2007-08-03 17:17:52 · answer #4 · answered by Jed 2 · 0⤊ 0⤋
(x - 5) * (x^2 + 2)
2007-08-03 17:00:49 · answer #5 · answered by lithiumdeuteride 7 · 0⤊ 0⤋