There are 2 quarters, 3 nickels, and 4 pennies in a cup. Suppose 2 coins are to be selected at random without replacement. What is the probability of selecting a quarter and then a penny?
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From a group of 6 men and 4 women, how many committees of 2 men and 3 women can be formed?:
2007-08-03 16:31:29 · 4 answers · asked by t.wes87 2 in Science & Mathematics ➔ Mathematics
The probablity of selecting a quarter first is 2/9. The probibility of selecting a penny next is 4/8. Thus the probability of selcting both sequentially, is 8/72 or 1/9, around 11% probability.
There are 15 possible combinations of men, and 4 possible combinations of women. Thus, there are 60 possible committiees which can be formed.
2007-08-03 16:42:54 · answer #1 · answered by lustatfirstbite 5 · 1⤊ 1⤋
The money question: Prob= 2/9 * 4/8 = 1/9
(the first probability is that of picking a quarter. The second is probability of picking a penny after the quarter is picked).
From the 6 men, you can pick 6!/4!2! or 15 different combinations of 2. You can pick 4 combinations of women for groups of 3 chosen from four. The product is the number of committees with different people or 60.
2007-08-03 23:42:41 · answer #2 · answered by cattbarf 7 · 2⤊ 1⤋
2quarters..+3..+4penny=9 in total
possiblity to get a quarter AND then a penny
2/9 * 4/8 = 1/9
+++++++++++++++++++++++++++++
6men..+4women... =10 in total
1 men AND 1men AND 1women AND 1women AND 1women
=6/10 * 5/9 * 4/8 * 3/7 *2/6 =3/126 = 1/42
am I right ?
2007-08-03 23:40:46 · answer #3 · answered by cOPYcAT 5 · 1⤊ 1⤋
Answer 2 first ? is 2 over nine quarters and 4 over nine for pennies. That would be a total probability of 6 over nine as final answer. And for 2nd ? is 5 over 10 for final answer.
2007-08-03 23:40:36 · answer #4 · answered by Cassy 2 · 0⤊ 1⤋