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factor the polynomial completely, if it is prime say so.

2007-08-03 16:27:15 · 5 answers · asked by mustang_muscle06 1 in Science & Mathematics Mathematics

5 answers

32a^2+4a-6
=2(16a^2+2a-3)
=2(16a^2+8a-6a-3)
=2{8a(2a+1)-3(2a+1)}
=2(2a+1)(8a-3)

2007-08-03 16:30:57 · answer #1 · answered by alpha 7 · 3 0

32a^2+4a-6 Divide all terms by 2
2(16a+2a-3)
2(2a+1)(8a-3)

2007-08-03 16:32:07 · answer #2 · answered by txmama423 3 · 0 1

32a^2+4a-6 = 2*(16a^2+2a-3) =2*(8a-3)(2a+1)

2007-08-03 16:30:27 · answer #3 · answered by nyphdinmd 7 · 1 0

2 * (2*a + 1) * (8*a - 3)

2007-08-03 16:31:17 · answer #4 · answered by lithiumdeuteride 7 · 0 1

2(8a-3)(2a-1)

2007-08-03 16:37:55 · answer #5 · answered by Jed 2 · 0 1

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