factor each difference or sum of cubes
2007-08-03 16:25:24 · 4 answers · asked by mustang_muscle06 1 in Science & Mathematics ➔ Mathematics
u^3-125v^3
=(u)^3-(5v)^3
=(u-v){(u)^2+u*5v+(5v)^2}
=(u-v)(u^2+5uv+25v^2)
2007-08-03 16:34:29 · answer #1 · answered by alpha 7 · 2⤊ 0⤋
This is a difference of two cubes (of the form "a^3 - b^3", with a=u and b = 5v). One factor is therefore "a-b" or (u - 5v). Divide to get the other polynomial factor.
Hope that helps.
2007-08-03 16:30:30 · answer #2 · answered by Anonymous · 0⤊ 1⤋
(u-5V)(u^2-5uv+25v^2)
General formula for difference of cube factoring.
2007-08-03 16:30:31 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
difference of cubes is (u-5v)^3 because if you multiply out u-5v three times, you get that original polynomial
2007-08-03 16:29:27 · answer #4 · answered by Sudha M 2 · 0⤊ 1⤋