A sample of SO2 gas which weighs 0.81 grams has a volume of 1.20 liters when collected at 25 degrees celisus.What would be the pressure of the gas sample?
2007-08-03 12:57:07 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
PV=nRT
P= pressure
V= volume (liters)
n= # of moles
R= A constant; value= 8.314
T= temperature (in Kelvin)
You are given the mass, so change it to moles. Then substitute the known values in the equation and you can find the pressure of sulfur dioxide gas.
2007-08-03 13:27:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
A STP, 64g SO2 occupies 22.4 L, so 0.81g would occupy
0.81*22.4/64 = 0.2835 L
Trom the Ideal Gas Law,
P1V1/T1 = P2V2/T2
P2 = P1(T2/T1)(V1/V2)
P2 = (760 T.)(298/293)(0.2835/1.20)
P2 â 183 Torr.
2007-08-03 20:30:10 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
????i have no clue and why do u wanna know that????
2007-08-03 20:02:14 · answer #3 · answered by nicky n 1 · 0⤊ 0⤋