to answer that, we experiment on 7^x by having different values of x. when x=1, 7^1=7, units digit = 7
x=2, 7^2=49 = 9
x=3, 7^3=343 = 3
x=4, 7^4=2401 = 1
x=5, 7^5=16,807 = 7
x=6, 7^6=117649 =9
this pattern goes on and follows: 7-9-3-1-7-9-3-1....in intervals of 4. thus, among the choices, C)5 cant be the last digit. there you go :D
2007-08-03 12:24:44
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answer #1
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answered by mikael 3
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Unit's digit is the last digit of a whole number.2 is the units digit of 12.6 is the units digiy of 236 and so on
if x is a positive integer
7^1=7
7^2=49
7^3=49*7=343
7^4=343*7=2401
7^5=2401*7=16807
7^6=16807*7=117649
7^7=117649*7=823543
7^8=823543*7=5764801
From the above table you may notice that the units digit will go on repeating 7,9,3 and 1 and no other digit excepting these 4 digits is possible as units digit.hence 5 is the odd digit out.
2007-08-03 12:29:31
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answer #2
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answered by alpha 7
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The units digit is also known as the ones digit (the digit to the left of the decimal when the number is written with one).
To solve this problem simply multiply like normal, but only keeping the units digit (that's the only part that's relevant):
7^1 >>> 7
7^2 >>> 9
7^3 >>> 3
7^4 >>> 1
7^5 >>> 7
As you can see the pattern starts to repeat, so looking at your options 5 (C) is the only number that isn't in the pattern.
2007-08-03 12:19:18
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answer #3
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answered by Anonymous
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"Units digit" is the one's place or the last digit
of the number.
Let's rule out the other answers by a counterexample:
7² = 49, so E is out
7³ = 343, so B is out
7^4 = 2401, so A is out
finally,
7^1 = 7 so D is out.
So, by elimination, C is the answer.
Another solution:
If 7^x ended in 5, then 5 would have to
be a divisor of 7^x, which is impossible.
So again, C is the answer.
2007-08-03 14:05:23
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answer #4
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answered by steiner1745 7
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7^1 = 7 so answer is not D
7^2 = 49 so answer cannot be E
7^3 = 343 so answer cannot be B
7^4 =2401 so answer cannot be A
After this the sequence repeats with the last digits being 7,9,3,1 over and over. So answer is C = 5
But it is also true that the units digit cannot be 2,4,5,6,8,or 0.
2007-08-03 12:42:51
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answer #5
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answered by ironduke8159 7
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The "units digit" is a different term for "ones digit".
In the number 354, 3 is the hundreds digit, 5 the tens digit, and 4 the ones digit or units digit.
2007-08-03 12:19:40
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answer #6
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answered by Automation Wizard 6
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The units digit is the 1's place (right-most in a non-decimal number).
Think of multiples of 7. 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77 (they begin to repeat the units digit). The only number missing is C. 5.
2007-08-03 12:19:07
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answer #7
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answered by JM 4
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Successive powers of 7 end in 7, 9, 3, 1 endlessly. There is never a 5 on the end.
2007-08-03 12:19:58
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answer #8
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answered by Anonymous
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The answer is 4 Let's try to make this easier for you: Lets call the "c" "cats" and instead of the "4", you write "something" So your equation will read: 4 cats = 3 cats + something. Can you see that the "something"(4) is actually the 1 missing cat? But how did we actually get there? Back to the actual sum 4c = 3c + 4 We need to get rid of as many c's as possible to simplify things, so you take the lowest number of c's (3c) and deduct it from both sides like this: (4c - 3c) = (3c - 3c) + 4 = 1c = 4 Does that make sense to you?
2016-05-17 11:07:38
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answer #9
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answered by alba 3
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