2007-08-03 11:08:15 · 12 answers · asked by hope 5 in Sports ➔ Baseball
Official MLB Rule 5.10c(1): If an accident to a runner is such as to prevent him from proceeding to a base to which he is entitled, as on a home run hit out of the playing field, or an award of one or more bases, a substitute runner shall be permitted to complete the play.
2007-08-03 11:23:22 · answer #1 · answered by Laying Low- Not an Ivy Leaguer 7 · 2⤊ 0⤋
This actually happened a couple of years ago to former Red Sox player Gabe Kapler. He hit a shot and wasn't sure if it was gone or not. As he was rounding second he saw the ball just clear the wall and went from a full sprint and tried to slow down. He broke his leg on the turf and couldn't continue, and a pinch runner finished his homerun trot. He was carried off.
2007-08-03 19:28:09 · answer #2 · answered by Anonymous · 2⤊ 1⤋
Worth noting, the pinch runner is credited the run scored. The injured batter-runner gets everything else.
2007-08-03 18:36:41 · answer #3 · answered by Chipmaker Authentic 7 · 0⤊ 0⤋
They call in a pinch runner.
Kapler tore his Achilles tendon. He's now managing one of the Red Sox single-A teams
2007-08-03 20:56:32 · answer #4 · answered by Magilla G 2 · 0⤊ 0⤋
A pinch-runner can be put in to finish running the bases for him.
2007-08-03 18:11:23 · answer #5 · answered by Answerman 3 · 1⤊ 0⤋
Pinch runner will finish the jog to home.
2007-08-03 18:15:54 · answer #6 · answered by Mariners24 4 · 0⤊ 0⤋
rule 5.10(c)(1) indicates that a pinch runner can be employed between bases for a player put out due to injury
2007-08-03 18:13:22 · answer #7 · answered by jsied96 5 · 1⤊ 0⤋
Remember Kirk Gibson's world series homer!
Dude could barely walk but there was no way that he was not going to make home plate!
2007-08-04 15:02:38 · answer #8 · answered by Anonymous · 0⤊ 0⤋
A pinch-runner takes his place.
2007-08-03 22:19:35 · answer #9 · answered by Ryan R 6 · 0⤊ 0⤋
The manager wonders why his player is so fragile that he broke his leg while jogging slowly.
2007-08-05 23:16:50 · answer #10 · answered by Joe H 2 · 0⤊ 0⤋