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I have a TI-89 calculator and I know there is a way to enter it in the calculator, but I can't remember how to do it. The 2 is in subscript.

2007-08-03 08:15:46 · 6 answers · asked by jjodom1010 3 in Science & Mathematics Mathematics

6 answers

I never had an 89, I had an 83. There wasn't a way to enter alternate log bases (except ln, of course), so we used the law that log base a of b = (log base c of b)/(log base c of a)
So I would have entered it as [(log 5)/(log 2)]
I know that doesn't answer the question, but you can at least do the work now, right?

2007-08-03 08:22:27 · answer #1 · answered by lockedjew 5 · 4 0

Log2 Calculator

2016-10-04 08:27:52 · answer #2 · answered by ? 4 · 0 0

This Site Might Help You.

RE:
How do I enter log2(5) in a calculator?
I have a TI-89 calculator and I know there is a way to enter it in the calculator, but I can't remember how to do it. The 2 is in subscript.

2015-08-06 05:02:43 · answer #3 · answered by Anonymous · 0 0

Last time I tried to use a TI-89 calculator, I couldn't figure out how to invoke the log function, let alone a logarithm to an arbitrary base. However, most calculators have buttons only for log to the base 10 or log to the base e, where e ≈ 2.718. This, however, is enough to compute to an arbitrary base a, by invoking the identity

loga (x) = log (x) / log (a)

where loga (x) is log to the base a of x,
log (x) is the log to any convenient base of x, and
log (a) is the log to that same base of a. It doesn't matter whether you use the log or ln button for this calculation.

2007-08-03 08:46:15 · answer #4 · answered by devilsadvocate1728 6 · 0 0

Use the change of log formula: log 5 base 10 divided by log 2 base 10. For most calculators you can not change the base 10 for log.

2007-08-03 08:23:53 · answer #5 · answered by Anonymous · 0 0

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cos²33 means [cos33]² ie cos33 all squared this is so it doesn't get confused with cos(33²) find cos33 first then square it cos, 33, =, x² gives 0.703368.... some calculators are different and you need to put the 33 before the cos .,,.,.

2016-04-05 23:01:08 · answer #6 · answered by ? 4 · 0 0

[log10(5) / log10(2)].

The 10 is in subscript.

2007-08-03 08:21:30 · answer #7 · answered by applebeans 2 · 1 0

I don't know what to say

2016-07-30 00:41:18 · answer #8 · answered by ? 3 · 0 0

try ln(5)/ln(2)

or log(5)/log(2)

2007-08-03 08:23:09 · answer #9 · answered by Amit Y 5 · 2 0

why are all the answers so dull and short these days?

2016-08-24 10:53:35 · answer #10 · answered by ? 4 · 0 0

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