Find the complex number z if:
z*=3z+5+2i (z* is the complex conjugate)
2007-08-03 07:52:41 · 5 answers · asked by Joey 1 in Science & Mathematics ➔ Mathematics
Write z=x+iy where x and y are real. Then you have
x-iy=3(x+iy)+5+2i, so
x-iy=(3x+5)+(3y+2)i.
Equating real and imaginary parts gives
x=3x+5 and
-y=3y+2.
This gives x=-5/2 and y=-1/2, so
z=(-5/2)+i(-1/2)
2007-08-03 07:58:38 · answer #1 · answered by mathematician 7 · 3⤊ 0⤋
z = - (5+i)/2
2007-08-03 15:00:10 · answer #2 · answered by iamshaleenmishra 1 · 0⤊ 0⤋
If z= x+iy
x-yi= 3x+3iy +5+2i
so 2x+5+i(4y+2)=0and 2x+5=0 x=-5/2 and y=-1/2
2007-08-03 15:00:03 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
x - i y = 3x + 3 i y + 5 + 2 i
x - i y = (3x + 5) + i (3y + 2)
x = 3x + 5
2x = - 5
x = - 5 / 2
- 1 = 3y + 2
3y = - 3
y = - 1
Solution is x = - 5 / 2 , y = - 1
2007-08-03 15:30:51 · answer #4 · answered by Como 7 · 1⤊ 0⤋
DUH!!!, "z" isn't a number, retard....it's a LETTER.
2007-08-03 15:01:13 · answer #5 · answered by Anonymous · 0⤊ 2⤋