(4√5-3√2)(2√5+4√2),
im getting 16+10√10....as the answer
is this the correct answer?
2007-08-03 07:44:19 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
8(5) + 16sqrt(10) - 6sqrt(10) - 12(2)
= 40 + 10sqrt(10) - 24
= 16 + 10sqrt(10)
You are correct!
2007-08-03 07:46:44 · answer #1 · answered by MsMath 7 · 2⤊ 1⤋
(4â5-3â2)(2â5+4â2)
= 8(â5)^2 + 16â10 - 6â10 - 12(â2)^2
= 40 + 16â10 - 6â10 - 24
= 16 + 10â10
2007-08-03 07:49:37 · answer #2 · answered by fofo m 3 · 2⤊ 0⤋
(4â5 - 3â2)(2â5 + 4â2) =
4 x 2â5â5 - 3 x 2â2â5 - 4 x 4â5â2 - 3 x 4â2â2 =
8â25 - 6â10 + 16â10 - 12â4
8 X 5 + 10â10 - 12 X 2
40 + 10â10 - 24
16 + 10â10
- - - - - - - - -s-
2007-08-03 08:45:39 · answer #3 · answered by SAMUEL D 7 · 2⤊ 0⤋
= (8 x 5) + 16â10 - 6â10 - (12 x 2)
= 40 + 10â10 - 24
= 16 + 10â10 (which agrees with your solution)
2007-08-03 08:24:54 · answer #4 · answered by Como 7 · 2⤊ 0⤋
(4â5-3â2)(2â5+4â2)
FOIL, keeping what's under the radical still under the radical.
= (4â5)*(2â5) + (4â5)*(4â2) + (-3â2)*(2â5) + (-3â2)*(4â2)
= (8â25) + (16â10) + (-6â10) + (-12â4)
= (8*5) + 10â10 - (12*2)
= 40 + 10â10 - 24
= 16 + 10â10
You are correct.
2007-08-03 07:47:35 · answer #5 · answered by Reese 4 · 2⤊ 0⤋
Well, it's a multiplication of binomial expressions, so we FOIL.
4*5^.5 * 2*5^.5 + 4*5^.5 * 4*2^.5 -3*2^.5 * 2*5^.5 - 3*2^.5 * 4*2^.5
8*25^.5 + 16*10^.5 - 6*10^.5 - 12*4^.5
8*5 - 10*10^.5 - 12*2
16 - 10*10^.5
Yup.
2007-08-03 07:50:03 · answer #6 · answered by lockedjew 5 · 2⤊ 0⤋
Correct, you have indeed FOILed the expression correctly.
2007-08-03 07:47:48 · answer #7 · answered by AibohphobiA 4 · 2⤊ 0⤋
yep... you got it...
2007-08-03 07:48:58 · answer #8 · answered by chandlar t 2 · 2⤊ 0⤋