lo (3+x)-log(x-4)=log 2 ?

Answer 1

log [ (x + 3) / (x - 4) ] = log 2
(x + 3) / (x - 4) = 2
x + 3 = 2x - 8
x = 11

Answer 2

log (3+x) - log (x-4) = log 2
By one of the laws, log n - log m = log (n/m). Therefore,
log [(3+x)/(x-4)] = log 2
Now, convert to normal form. If log base a of c = b, then a^b = c. These are in base 10:
10 ^ (log 2) = (3+x)/(x-4)
By some other law, a ^(log base a of b) = b. The left side matches this, with base of the exponent and base of the log equal to 10. Therefore, the left side equals 2.
2 = (3+x)/(x-4)
2(x-4) = (3+x)
2x - 8 = 3 + x
x = 11

Answer 3

Log(x+3)/(x-4)=Log2

(x+3)/(x-4)=2..........2(x-4)=x+3.......2x-8=x+3......x=11

Answer 4

log(3 + x) - log(x - 4) = log2

log[(3 + x)/(x - 4)] = log2

(3 + x)/(x - 4) = 2

3 + x = 2(x - 4)

3 + x = 2x - 8

x = 11

Check it with your calculator - you will find that it works!

Answer 5

log((3 + x) / (x - 4)) = 2
(3 + x) / (x - 4) = 2
3 + x = 2x - 8
x = 11

I used the property that log(a) - log(b) = log(a/b), and from there the rest was straightforward algebra.

Answer 6

log(a)-log(b)=log(a/b)
log[(3+x)/(x-4)]=log(2)
(3+x)/(x-4)=2 (cancel out the logs)
(3+x)=2(x-4)
3+x=2x-8
-x=-11
x=11

Answer 7

(3+X)/X-4 =2 then 3+X = 2X -8
then X=11